In today's deal, played in a social game, declarer's only concern was to
find a sure line to secure nine tricks.
Overtricks were irrelevant.
Both sides vulnerable North deals
|
West |
North |
East |
South |
|
|
1 |
Pass |
2NT |
|
Pass |
3NT |
End |
|
Opening Lead:
4
West led the
4,
nine, eight (high to show an even number),
queen. Declarer led the
7
to dummy's king and East took his ace to
return the
3.
Declarer won the ace and ran clubs. West had
to find three discards; two diamonds are
easy but his remaining discard would allow
declarer to make the contract if he could
guess the position. A heart discard would
allow declarer to build a diamond trick
safely as West could cash only two heart
winners. West saw this coming and so made
his first discard a spade, coming down to
the singleton jack. Declarer duly finessed
the
10,
but West's hand was high; two down.
Declarer had incorrectly guessed the endgame. A diamond play instead would
not have worked, but the odds-against play
of a spade to the queen (intending to play a
diamond if the jack did not fall) would have
succeeded, Was declarer simply unlucky to go
set on the line he selected?
The short answer is "no." If, at trick two, declarer leads a club to dummy
to play the
5
away from the king, there is no defence to
beat him. If East goes in with the
A to
clear hearts, declarer has two spade tricks,
two hearts, and five clubs. If East ducks
his ace, the
Q wins and declarer builds a
diamond for his ninth winner. If West can
take declarer's $Q with the ace he can't
attack hearts so must play either a diamond,
giving declarer his ninth trick there, or a
spade, giving declarer time to build a
diamond while his ten-nine of spades stand
guard against the jack.
The bottom line: if East has the
A, lead the first spade "through" him
because he might beat you if you lose an
honour to him. If West has the
A, any spade
play works.